The given diagram shows a ticker tape. The frequency of the ticker tape is 20 Hz.How much time will be taken by the ticker tape to plot dots from P to T?
Correct answer: B. 0.25 s.
- A. 0.05 s.
- B. 0.25 s.
- C. 5 s.
- D. 20 s.
Explanation
* Frequency of the ticker tape (f) = 20 Hz * The diagram shows dots labeled P, Q, R, S, T.Calculations: * Calculate the time period (T) for one interval: The time period is the inverse of the frequency. T = 1 / f = 1 / 20 Hz = 0.05 seconds. This means that 0.05 seconds elapses between the plotting of two consecutive dots. * Count the number of intervals from P to T: Looking at the diagram, the dots are P, Q, R, S, T. * Interval 1: From P to Q * Interval 2: From Q to R * Interval 3: From R to S * Interval 4: From S to T Visually, there are 4 intervals between point P and point T. * Calculate the total time for 4 intervals: Total Time = Number of intervals × Time per interval Total Time = 4 × 0.05 s = 0.20 s.
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