The given diagram shows a helical spring attached to a fixed surface. The value of spring constant is taken as 'k' 300 N/m and a 100 N weight is attached at the bottom.The extension in the spring will be

Explanation

The correct answer is 0.333 m. When a weight is attached to the spring, it exerts a force on the spring, causing it to extend. By applying Hooke's Law (F = kx), where F is the force, k is the spring constant, and x is the extension, we can calculate the extension in the spring to be 0.333 meters. Options B, C, and D are incorrect because they do not account for the force exerted by the weight of the object, leading to incorrect extension calculations.