The full-load copper loss of a trans¬former is 1600 W. At half-load, the copper loss will be___________?
Correct answer: D. 400 W
- A. 6400 W
- B. 1600 W
- C. 800 W
- D. 400 W
Explanation
Copper loss varies as the square of load current: Pcu ∝ I². At half-load it is (1/2)² × 1600 = 400 W, so the loss becomes one-fourth of full-load loss.
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