The front of a roller-coaster car is at the bottom of a hill and is 15 feet above the ground. If the front of the roller-coaster car rises at a constant rate of 8 feet per second, which of the following equations gives the height h, in feet, of the front of the roller-coaster car s seconds after it starts up the hill?
Correct answer: A. h = 8s + 15
- A. h = 8s + 15
- B. h = 15s + 335/8
- C. h = 8s + 335/15
- D. h = 15s + 8
Explanation
Choice A is correct. It's given that the front of the roller-coaster car starts rising when it's 15 feet above the ground. This initial height of 15 feet can be represented by a constant term, 15, in an equation. Each second, the front of the roller-coaster car rises 8 feet, which can be represented by 8s. Thus, the equation h = 8s + 15 gives the height, in feet, of the front of the roller-coaster car s seconds after it starts up the hill.
Last updated
Related questions
(1/2x+1) + 5Which of the following is equivalent to the expression above for x > 0?
1/400 in percentage =
100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:
|14| * |-2|=?