The frequency of incident light falling on a photo sensitive plate is doubled, then maximum kinetic energy of the emitted photoelectrons will become:
Correct answer: B. More than 2 times of the earlier value
- A. 2 times of the earlier value
- B. More than 2 times of the earlier value
- C. Less than 2 times of the earlier value
- D. Unchanged
Explanation
Le hv0−W0=KIf frequency is doubled, let kinetic energy of photoelectrons be K12hv−W0=K1⇒2(hv−W0)+W0=K1⇒2K+W0=K1Kinetic energy will be more than doubled.Hence, this option is correct.
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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