The frequency of a particle performing circular motion changes from 60 rpm to 180 rpm in 20s, then the angular acceleration is:
Correct answer: B. 0.2π rad/s2
- A. 0.1π rad/s2
- B. 0.2π rad/s2
- C. 0.3π rad/s2
- D. 0.4π rad/s2
Explanation
Angular acceleration=Change in angular velocity/timeω1 = 60 rpm= 60×2π rad/60s = 2π rad/sω2 = 180 rpm= 180×2π rad/60s = 6π rad/s Putting values in above formula α = 6π rad/s - 2π rad/s / 20s α = 4π rad/s / 20s α = 0.2 rad/s2Hence,B is the correct option.
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About Angular Velocity
Angular velocity describes how quickly angular displacement changes with time, with ω = Δθ/Δt and units of radians per second. Questions relate angular and linear motion through v = rω, use the direction given by the right hand rule, and distinguish angular velocity from angular acceleration and ordinary frequency.
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