The force required to stretch a steel wire 1 sq. cm in cross section to double its length is (given y=2×10^11N/m2)
Correct answer: C. 2 × 10^7 N
- A. 10^7 N
- B. 10^11N
- C. 2 × 10^7 N
- D. 2 x 10^11 N
Explanation
The force (F) required to stretch a wire can be calculated using Hooke's Law: F=Y⋅A⋅ΔL/L , where:Y is the Young's modulus,A is the cross-sectional area,ΔL is the change in length,L is the original length.Given that the cross-sectional area remains constant, we have A=1cm^2.The change in length (ΔL) is double the original length, so ΔL=2L.Substituting the values into Hooke's Law, we get: F =2×10^7N
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