The force 'F' on a charged partied 'q' moving with velocity ;v' parallel to magnetic held 'B' is given by:
Correct answer: C. F = 0
- A. F = qvB
- B. F = qE
- C. F = 0
- D. F = mv2/r
Explanation
When a charged particle moves parallel to a magnetic field, the force acting on it is zero because the angle between the velocity and magnetic field is 0 degrees, resulting in sin(0) = 0. Therefore, the correct answer is Option C. Option A and Option B are incorrect as they represent formulas for different fields, while Option D is incorrect as it represents the formula for centripetal force, not magnetic force.
This question appeared on the ETEA MDCAT 2013 paper, which you can sit online with every answer explained.
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About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
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