The force 'F' on a charged partied 'q' moving with velocity ;v' parallel to magnetic held 'B' is given by:
Correct answer: C. F = 0
- A. F = qvB
- B. F = qE
- C. F = 0
- D. F = mv2/r
Explanation
When a charged particle moves parallel to a magnetic field, the force acting on it is zero because the angle between the velocity and magnetic field is 0 degrees, resulting in sin(0) = 0. Therefore, the correct answer is Option C. Option A and Option B are incorrect as they represent formulas for different fields, while Option D is incorrect as it represents the formula for centripetal force, not magnetic force.
Last updated
About Charged Particle in a Magnetic Field
A charged particle moving through a magnetic field experiences the Lorentz force, which is perpendicular to both its velocity and the field. The motion may be circular or helical, with questions involving radius, angular frequency, time period, and work done. A stationary charge feels no magnetic force.
Practise Electromagnetism
1,176 free Electromagnetism MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
A charge is at rest in a magnetic field, then the magnetic force on charge is:
A charge is moving with velocity v, it enters a uniform magnetic field B. The direction of v is perpendicular to B. What is the path of the charge particle inside the magnetic field?
A charge of two microcoulombs (2 μC) moves with velocity of two meter per second (2 m/sec) in the direction of two Tesla magnetic field. The force that will act on it will be:
A charge projected with velocity of 10 m/s in a magnetic field of 10 T at an angle of 60°, if force exerted on charge is 2.78 x 10^-17 N, then value of charge is:
A charged particle entering a uniform magnetic field at right angles to it follows