The force experienced by the wall on which water strikes normally at the rate of 10ms-1 and discharge of 0.0001ms-1 is
Correct answer: A. 1N
- A. 1N
- B. 10N
- C. 100N
- D. None
Explanation
Given:- Velocity of water (v) = 10 m/s- Discharge rate (Q) = 0.0001 m³/sCalculating Momentum:Momentum (p) is given by the formula: Momentum = mass × velocityThe mass of water per second is calculated using the discharge rate (Q) and density of water (ρ):Mass = ρ × QGiven that the density of water (ρ) is approximately 1000 kg/m³:Mass = 1000 × 0.0001 = 0.1 kgMomentum = Mass × Velocity = 0.1 × 10 = 1 kg m/sCalculating Force:The force experienced by the wall is equal to the rate of change of momentum.Force = Rate of change of momentum = MomentumForce = 1 NThe calculated force experienced by the wall due to the water striking it is 1 N, as derived from the rate of change of momentum.
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