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The force between two charges Q and q, separated by a distance is F. What will be the force between them when the distance between them is d/2?

Correct answer: A. 4 F

  • A. 4 F
  • B. 2 F
  • C. F
  • D. F/2

Explanation

According to Coulomb's law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.F= kq1q2/d2According to the given statement,1st case, q1= q q2= Q And Force F = kqQ/d2 2nd case, d= d/2Now putting the value of d/2 , F*= kqQ/(d/2)2 F*= kqQ/d2/4 F*= 4 kqQ/d2 [ where kqQ/d2 = F the first case force]Hence , F*= 4 F

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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.

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