The following heat engine produces power of 100,000 kW. The heat engine operates between 800 K and 300 K. It has a thermal efficiency equal to 50% of that of the Carnot engine for the same temperature. The rate at which heat is absorbed from the hot reservoir is____________________?
Correct answer: D. 320,000 kW
- A. 100,000 kW
- B. 160,000 kW
- C. 200,000 kW
- D. 320,000 kW
Explanation
The Carnot efficiency is 1 - 300/800 = 0.625, so the engine efficiency is 0.5(0.625) = 0.3125. Since power = efficiency times heat input, the required heat input is 100,000/0.3125 = 320,000 kW.
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