The fission of 239Pu94 produces two fragments with kinetic energies in the ratio 3:2. The mass ratio of the fragments is:
Correct answer: A. 2:3
- A. 2:3
- B. 3:2
- C. 2:1
- D. 3:1
Explanation
By conservation of momentum, m1 v1 = m2 v2 . Kinetic energy KE = (1/2)mv2 , so KE1 /KE2 = (m1v12)/(m2v22) = 3/2. Since v2 /v1 = m1/m2 , then 3/2 = (m1/m2 ) × (m1/m2)2 = (m1/m2)3.Thus, m1 /m2 = (3/2)(1/3), but for kinetic energy ratio, m1 /m2 = 2/3.
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