The first resonance length in a closed pipe is 20 cm. Then the second resonance occurs at:
Correct answer: B. 90 cm
- A. 60 cm
- B. 90 cm
- C. 120 cm
- D. 80 cm
Explanation
In a closed pipe, the fundamental frequency is produced when the length of the pipe is one-fourth of the wavelength. For the second resonance, the length of the pipe is three-fourths of the wavelength. Therefore, the second resonance length would be 3×20cm=60cm.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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