The figure below shows three circular arcs, each of radius R and total charge as indicated. The net electric potential at the center of curvature is:
Correct answer: A. The net electric potential is proportional to the sum of the charges divided by the radius R.
- A. The net electric potential is proportional to the sum of the charges divided by the radius R.
- B. The net electric potential is zero due to symmetry.
- C. The net electric potential depends only on the largest charge.
- D. The net electric potential is inversely proportional to the sum of the charges.
Explanation
The net electric potential at the center of curvature due to each arc is the sum of potentials from each arc. For a single arc with charge Q and radius R, the potential is given by V = kQ/R. Since potential is a scalar, the total potential is the algebraic sum of the potentials due to each arc. Hence, the correct approach is to calculate the potential due to each arc and sum them up.Option A is correct because it considers the contribution of all charges, while Option B incorrectly assumes symmetry leads to zero potential. Option C is incorrect as it ignores the contributions of smaller charges, and Option D is incorrect as it misrepresents the relationship between potential and charge.
Last updated
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1/C_eq = 1/C_1 + 1/C_2 + 1/C_3 + ... + 1/C_n
1 N/C equals to:
1 volt x 1 ampere is equal to:
10 V potential difference is applied across the plate of the 1 µF capacitor. What is the energy stored in the capacitor?
12 J work is to be done against an existing electric field to take a charge of 0.01C from A to B. Find the potential difference between B and A: