The extension in a string, obeying Hooke's law, is x. The speed of sound in the stretched string is v. If the extension in the string is increased to 1.5x, the speed of sound will be:
Correct answer: A. 1.22v
- A. 1.22v
- B. 0.61v
- C. 1.50v
- D. 0.75v
Explanation
(SOLUTION1) Speed of sound V= (T/m)square root Where m is the mass per unit length From here we can see that V is proportional to (T)square root Also, T is proportional to x So, V2/V1 = (1.5x/x)square root V2= (1.5square root) x V1 V2= 1.22V1 (SOLUTION 2) Following is the solution to this question:
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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