The escape velocity from the earth's surface is 11km/s. A certain planet has a radius twice that of the earth but its mean density is the same as that of the earth. The value of the escape velocity from this planet would be
Correct answer: C. 5.5km/s
- A. 24km/s
- B. 11km/s
- C. 5.5km/s
- D. 16.5km/
Explanation
Escape velocity is (ve ) is given by the formula:ve = √2GM/R
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