The equivalent diameter for pressure drop calculation for a fluid flowing through a rectangular cross-section channels having sides 'x' & 'y' is given by_________________?
Correct answer: A. 2xy/(x + y)
- A. 2xy/(x + y)
- B. xy/(x + y)
- C. (x + y)/2xy
- D. (x + y)/xy
Explanation
The hydraulic or equivalent diameter is Dₑ = 4A/P. For a rectangular channel, A = xy and wetted perimeter P = 2(x + y), giving Dₑ = 2xy/(x + y).
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