The equivalent diameter for pressure drop calculation for a duct of square cross-section is given by (where, x = each side of the square duct) ?
Correct answer: A. x
- A. x
- B. √(πx)
- C. √(2x)
- D. √(x/2)
Explanation
The equivalent diameter is defined as 4A/P, where A is flow area and P is wetted perimeter. For a square, 4(x²)/(4x) gives x.
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