The equivalent diameter for fluid flow through square cross section channel of side 'x', for pressure drop calculation purpose is given by____________________?
Correct answer: D. x
- A. 4x
- B. 2x
- C. √x
- D. x
Explanation
The equivalent or hydraulic diameter is 4A/P, where A is flow area and P is wetted perimeter. For a square of side x, this becomes 4x²/(4x) = x.
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