The engine is supposed to work between 727 degree C and 227 degree C, then maximum possible efficiency is
Correct answer: A. 1/2
- A. 1/2
- B. 1/4
- C. 3/4
- D. 1
Explanation
Option A is correct since the formula of efficiency for a heat engine is 1-(T2/T1). So if the temperature of the heat source (T1) is 727 degrees celsius = 1000K and that of the heat sink (T2) is 227 degrees celsius = 500K. Therefore 1- (500/1000) = ½. Option B is incorrect since it states ¼ which is not the correct answer Option C is incorrect since it states ¾ which is not the correct answer Option D is correct since it states 1 which is not correct.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More First Law of Thermodynamics questions
If dU and dW represent internal energy and work done then which is true?
During adiabatic expansion internal energy decreases by 2J, then work done in this process is:
Which of the following processes is reversible?
Work done in an adiabatic process of gas from T1 to T2 is
Under a cyclic path, internal energy after the complete cycle is the same as:
The efficiency of the heat engine can be increased by: