The energy absorbed as heat by an ideal gas for an isothermal process is equal to:
Correct answer: A. The work done by the gas
- A. The work done by the gas
- B. The work done on the gas.
- C. Change in the internal energy of the gas
- D. Zero, since the process is isothermal
Explanation
During an isothermal process, temperature and internal energy remain unchanged. The first law of thermodynamics states that internal energy = heat transferred + work done. Heat absorbed is considered positive (what is happening here); heat loss is negative. Work done on gas is positive; work done by gas is negative.So when we put values in the equation0 = +heat transfer +work doneheat transfer = - work doneSince work done is negative, work is done by the gas which is option A.
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