The electronic configuration of four elements is given. Which of these elements has the highest first ionization energy?
Correct answer: A. 1s2, 2s2, 2p3
- A. 1s2, 2s2, 2p3
- B. 1s2, 2s2, 2p6, 3s1
- C. 1s2,2s2,2p4
- D. 1s2, 2s2, 2p6, 3s2, 3p3
Explanation
Option A is correct. The given element in option A has highest ionization energy as it has half filled p orbital which is comparatively more stable than partially filled p orbital. Hence, greater amount of energy is required to remove an electron from this element. It is extra stable configuration. Option B is incorrect (refer to the explanation in option B) Option C is incorrect (refer to the explanation in option C) Option D is also incorrect (refer to the explanation in option D)
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