The efficiency of the Carnot engine can never be 1, because:
Correct answer: D. We need cold resevoir at absolute zero temperature, which is not available
- A. We can not achieve the higher temperature
- B. We do not have an ideal working substance
- C. There are always enegy losses
- D. We need cold resevoir at absolute zero temperature, which is not available
Explanation
The efficiency of a Carnot engine is defined as the ratio of the work output to the heat input. According to the Carnot cycle, the maximum possible efficiency of an engine operating between two temperatures, T1 (higher temperature) and T2 (lower temperature), is given by the equation:Efficiency = 1 - (T2 / T1)For the efficiency to be 1 (100%), the temperature of the cold reservoir (T2) would have to be absolute zero (0 Kelvin). However, absolute zero temperature is not attainable in practice. Therefore, the efficiency of a Carnot engine can never reach 1.Options A, B, and C are not the correct explanations for why the efficiency of a Carnot engine cannot be 1. Option D provides the correct explanation that the unavailability of a cold reservoir at absolute zero temperature prevents the Carnot engine from achieving an efficiency of 1.Therefore, the correct answer is D).
Last updated
About Thermal Equilibrium and Heat
Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
100 W heater is switched on for 5 minutes to melt ice. What is the mass of ice that melts at 0oC? ( The specific latent heat of fusion of ice is 334 J/g).
100 W heater is used for 5 minutes to heat 500 g of water. What is the change in the temperature of the water? (The specific heat capacity of water is 4.2 J/gC).
100 W heater is used to melt 50 g of ice at 0°C. How long should the heater be switched on? (Specific latent heat of fusion of ice is 334 J/g)
100 W heater is used to melt 50 g of ice at OC. How long should the heater be switched on? (Specific latent heat of fusion of ice is 334 J/g)
100W heater is used for 5 minutes to heat 500g of water. What is the change in the temperature of water? (Specific heat capacity of water is 4.2 J/gC)