The e.m.f. generated by a shunt wound D.C. generator isE. Now while pole flux remains constant, if the speed of the generator is doubled, the e.m.f. generated will be_______________?
Correct answer: B. 2E
- A. E/2
- B. 2E
- C. slightly less than E
- D. E
Explanation
Generated e.m.f. follows E ∝ ΦN. With pole flux Φ constant, doubling speed N doubles the e.m.f., changing E to 2E.
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