The distance between two consecutive nodes of an incident wave is 2 m. If the frequency of the wave is 50 Hz, then the speed of this wave is
Correct answer: D. 200 m/s
- A. 25 m/s
- B. 50 m/s
- C. 100 m/s
- D. 200 m/s
Explanation
* Understanding the relationship between nodes and wavelength: The distance between two consecutive nodes of a wave is equal to half a wavelength (λ/2).* Given: Distance between two consecutive nodes = 2 m* Therefore, λ/2 = 2 m* So, the wavelength (λ) = 2 m * 2 = 4 m* Given Frequency:* Frequency (f) = 50 Hz* Calculating the speed of the wave: The speed of a wave (v) is calculated using the formula: v = f × λ* v = 50 Hz × 4 m* v = 200 m/s
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About Stationary Waves
Stationary waves form when two waves of the same frequency and amplitude travel in opposite directions and interfere. The topic covers nodes, antinodes, wavelength, phase, resonance, and the allowed frequencies on strings and in air columns. Unlike progressive waves, stationary waves do not transfer energy from one point to another.
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