The distance between node and anti-node is 85cm the velocity of sound is 340 ms-1 the frequency of waves is:
Correct answer: A. 100 Hz
- A. 100 Hz
- B. 250 Hz
- C. 200 Hz
- D. 340 Hz
Explanation
To solve this problem, we start with the fact that the distance between a node and an anti-node is λ/4, where λ is the wavelength. Given that this distance is 0.85 m, we have:λ/4 = 0.85 mTherefore, λ = 4 × 0.85 m = 3.4 m.The velocity of sound is given as 340 m/s. The frequency f can be calculated using the wave equation v = fλ, where v is the velocity:f = v/λ = 340 m/s / 3.4 m = 100 HzThus, the correct answer is 100 Hz.The other options are incorrect due to errors in the interpretation or calculation of wave parameters.
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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