The distance between node and anti-node is 85 cm the velocity of sound is 340 ms⁻¹ the frequency of waves is:
Correct answer: A. 100 Hz
- A. 100 Hz
- B. 250 Hz
- C. 200 Hz
- D. 340 Hz
Explanation
Node to antinode = λ/4 = 0.85 m ⇒ λ = 3.4 m. Frequency f = v/λ = 340/3.4 = 100 Hz. Thus, option A is correct.
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About Waves
Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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