The discharge through a semi-circular weir varies as (where, H = Head of liquid.) ?
Correct answer: B. H2
- A. H
- B. H2
- C. H3/2
- D. H1/2
Explanation
For a semicircular weir, the width of the opening increases approximately with the square root of depth, and integration with the velocity term gives discharge proportional to H squared. Hence the dependence is H² rather than the H^(3/2) relation commonly associated with a rectangular weir.
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