The dimensions of pressure is:
Correct answer: D. D
- A. A
- B. B
- C. C
- D. D
Explanation
The following is the solution:ππππ π π’ππ = πΉππππ/π΄πππBy dimensional analysis: ππππ π π’ππ = ππ. π. π β2/π2 Therefore, by simplification we get out answer:[MLTβ2]/[L2]=ML-1T-2The correct dimension of pressure: [MLTβ2]/[L2]=ML-1T-2
This question appeared on the UHS MDCAT 2015 paper, which you can sit online with every answer explained.
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About Dimensional Analysis
Dimensional analysis expresses physical quantities through fundamental dimensions such as mass, length and time. It checks dimensional consistency, helps derive relations and converts between unit systems, but cannot determine numerical constants or distinguish quantities with identical dimensions. Dimensional formulae must not be confused with complete physical units.
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