The dimensions of h/e (h = Planck's constant and e = electronic charge) are same as that of:

Explanation

The following is the solution: Plancks constant (h) has the units joule-seconds. the dimensions are =[ML2T−1], Electron charge (e) will have dimensions= [TI], Dimension for h/e will be [ML2T−2I−1], From the given options, Dimension for the electric field will be [M1L1I-1T-3], Dimension for magnetic flux will be [ML2T−2I−1], Dimension for electric flux will be [ML3T−3I−1], Dimension for the magnetic field will be [M1T-2I-1], Both magnetic flux and h/e will have the same dimensions.