The dimensions of gravitational constant "G" are:
Correct answer: D. [M-1L3T-2]
- A. [ML-2T-1]
- B. [ML-2T-2]
- C. [M2L-2T-1]
- D. [M-1L3T-2]
Explanation
Explanation: F = G (m1) (m2) / r² G = F (r²) / (m1) (m2) G = [MLT-2] [L²] / [M] [M] = [M-1L³T-2] These dimensions correspond to surface gravity or acceleration due to gravity. These dimensions correspond to force per unit mass or pressure. These dimensions correspond to the inverse of the square of a length or area.
This question appeared on the UHS MDCAT 2009 paper, which you can sit online with every answer explained.
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About Law of Universal Gravitation
Every two masses attract each other with a force proportional to the product of their masses and inversely proportional to the square of their separation, expressed as F = Gm₁m₂/r². Questions also involve the gravitational constant, vector direction, superposition of gravitational forces, and the distinction between gravitational force and gravitational field strength.
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