The diameter of a wire is measured by using a micrometer screw gauge with least count of 0.01 mm. Which of the following readings will be correct?
Correct answer: C. 2.00 mm
- A. 0.20 cm
- B. 0.002 m
- C. 2.00 mm
- D. 0.2 cm
Explanation
The following is the solution:Since least count is 0.01 mm, therefore, diameter must be expressed in multiples of 0.01.2.00 mm is 200 times 0.01 mm therefore, (C).
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