The diagram shows a current-carrying conductor RS of length 2m placed perpendicular to a magnetic field of flux density 0.5 tesla. The resulting force on the conductor is I N acting into the plane. of paper. What is the magnitude and direction of the current?
Correct answer: C. I A from S to R
- A. I A from R to S
- B. 2 A from R to S
- C. I A from S to R
- D. 2 A form S to R
Explanation
According to the right-hand rule direction of the current is from S to R. F = BIL sinθ 1 = 0.5 x I x 2 x sin90 1 = 0.5 x I x 2 x1 so, I = 1/0.5x2 = 1/1 =1A
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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