The de-Broglie wavelength associated with a particle moving at 10⁶ m/s and having mass 10⁻³⁰ kg:
Correct answer: A. 6.6 x 10^-10 m
- A. 6.6 x 10^-10 m
- B. 1.5×10⁶ m
- C. 1.9×10⁻⁵ m
- D. 7.2×10⁻⁸ m
Explanation
Step 1: Calculate the momentum (p)p=mv=10-24kgm/sStep 2: Calculate the de Broglie wavelengthNow, substitute p into the de Broglie wavelength formula:λ=hp=6.626×10−34 Js10−24 kg m/s=6.6x10-10m
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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