The correct order of hybridization of the central atom in the following species NH3, [PtCl4]-2 , PCl5 and BCl3 is :
Correct answer: B. sp3, dsp2, dsp3, sp2
- A. dsp2, dsp3, sp2, sp3
- B. sp3, dsp2, dsp3, sp2
- C. dsp2, sp2, sp3, dsp3
- D. dsp2, sp3, sp2, dsp3
Explanation
The hybridization of the central atoms can be determined based on the number of electron pairs and geometry:NH3: The nitrogen atom forms three bonds and has one lone pair, resulting in an sp3 hybridization.[PtCl4]2-: The platinum atom forms four bonds in a square planar geometry, indicating dsp2 hybridization.PCl5: The phosphorus atom forms five bonds, leading to dsp3 hybridization.BCl3: The boron atom forms three bonds with no lone pairs, resulting in sp2 hybridization.Thus, the correct order of hybridization is sp3, dsp2, dsp3, sp2, which matches Option B.
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