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The circuit shown in the figure, current through the 5 Ω resistor is:

Correct answer: C. Zero

  • A. 1A
  • B. 2A
  • C. Zero
  • D. 0.5A

Explanation

The given circuit is a balanced Wheatstone bridge. So, the current through the 5Ω resistor is zero. Hence, this option is correct.RAC=(8/4)=8×4/8+4=32/12=2.667 Ω.Path C→B→D resistance = 5+8=13 Ω.13 Ω in parallel with 16 Ω ⇒RCD=13×16/13+16=208/29=7.172 ΩReq=2.667+7.172=9.839 Ω. Itot=10/9.839=1.0166 AVoltage across C − D: V=Itot×RCD=1.0166×7.172=7.289 VCurrent through 5 Ω (same as through the CBD series):I=7.289/13=0.561 A≈0.56.

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Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.

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