The circuit shown in the figure contains two diodes each with a forward resistance of 50 Ω and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 Ω resistance (in ampere) is:
Correct answer: B. 0.02
- A. Zero
- B. 0.02
- C. 0.03
- D. 0.036
Explanation
The total resistance in the circuit is the sum of the diode resistances and the 100 Ω resistance, giving a total of 300 Ω.Using Ohm's law (V = IR), we find the current (I) by dividing the voltage (6 V) by the total resistance (300 Ω), resulting in a current of 0.02 A. The other options are incorrect because they either assume no current flow or miscalculate the total resistance or voltage drop. The correct answer is B, 0.02.D1 → F.B (Forward Bias), D2 R.B (Reverse Bias)I = Vnet/Rnet = 6/300 = 0.02A.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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