The charge flowing across the cell on closing the switch is equal to:
Correct answer: B. CV/2
- A. CV
- B. CV/2
- C. 2CV
- D. zero
Explanation
When the switch is kept open: Total capacitance (C) = ( 1/C + 1/C)-1 = (2/C)-1 = C/2 Total charge (Q) = total capacitance x total voltage = C/2 x V = CV/2 When the switch is closed: {Capacitor 2 gets short circuited and all the current flows through the switch path} Total capacitance (C') = C Total charge (Q') = C' x V = CV Charge flowing through cell (ΔQ) = Q' - Q = CV - CV/2 ΔQ = CV/2 .
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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