The change in internal energy of an ideal gas during an isothermal process is:
Correct answer: C. Zero
- A. Positive
- B. Negative
- C. Zero
- D. Equal to work done
Explanation
In isothermal process, temperature of ideal gas remains constant, its internal energy, depend only on temperature (U =(f/2)nRT), does not change, resulting ΔU = 0.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
Practise Thermodynamics
714 free Thermodynamics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More First Law of Thermodynamics questions
The internal energy of an ideal gas depends on:
A gas expands adiabatically, and its temperature decreases. The work done is:
The work done by a gas during an isothermal expansion is given by:
The heat transfer in a process where volume remains constant is equal to:
For an ideal gas undergoing adiabatic expansion, the relation between pressure and volume is:
System absorbs 500 J of heat and does 300 J of work. The change in internal energy is: