Asked in ETEA MDCAT 2012 2012Moderate

The centripetal force acting on a body rotating in a circle of radius ‗r' is ‗F'. If the body moves in a circle of radius half of the initial value keeping other quantities constant, then the percentage change in the centripetal force is:

Correct answer: B. 100%

  • A. 300%
  • B. 100%
  • C. 400%
  • D. 200%

Explanation

To solve this problem, we start with the formula for centripetal force: F = (mv^2)/r.Initially, the force is F. When the radius is halved, the new radius is r/2. The new force becomes F' = (mv^2)/(r/2) = 2F.The percentage change in force is given by: [(F' - F) / F] × 100% = [(2F - F) / F] × 100% = 100%.Thus, the correct answer is 100%, which corresponds to Option B. Options A, C, and D represent incorrect calculations of the percentage change based on the new radius, leading to incorrect force changes.

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