The capacitance of reversed bised junction J2 in a thyristor is CJ2 = 20 pF and can be assumed to be independant of the off state voltage. The limiting value of the charging current to turn on the thyristor is 16 mA. What is the critical value of dv/dt?
Correct answer: B. 800 V/µs
- A. 600 V/µs
- B. 800 V/µs
- C. 1200 V/µs
- D. 1000 V/µs
Explanation
The charging current is I = C(dv/dt), so dv/dt = 16 mA / 20 pF = 8 × 10^8 V/s = 800 V/µs. Therefore, option B is correct.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
Practise Power Electronics
253 free Power Electronics MCQs from Electrical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Electrical Engineering questions like this
Electrical Engineering is on 2 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Power Electronics questions
Gate circuit or triggering circuit of a thyristor is
Thyristor is nothing but a____________?
How can we protect SCR from thermal conditions _____________?
BCT is used for____________?
Let of a thyristor Vc1, Vc2, Vc3 are forward break over voltage for gate current Ig1, Ig2, Ig3 respectively. Then________________?
Which triggering is the most reliable____________?