The bond angle is H2S is less than H2O due to:
Correct answer: D. All of the above
- A. Small size of oxygen atom
- B. Greater electronegativity of oxygen atom
- C. Oxygen contains 2 lone pair of electrons
- D. All of the above
Explanation
The bond angle in H2S is less than in H2O due to the smaller size of oxygen and the presence of two lone pairs of electrons on the oxygen atom. The smaller size of oxygen allows for closer electron-electron repulsion, resulting in a larger bond angle in H2O. Additionally, the presence of two lone pairs of electrons on the oxygen atom in H2O further increases the electron-electron repulsion, pushing the hydrogen atoms closer together and resulting in a smaller bond angle in H2S.
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About VSEPR Theory
Valence shell electron pair repulsion theory predicts molecular shape by arranging bonding pairs and lone pairs around a central atom to minimize repulsion. Questions cover linear, trigonal planar, tetrahedral, trigonal bipyramidal and octahedral electron geometries, bond angles and distortions caused by lone pairs. Electron geometry is not always the same as molecular shape.
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