The bond angle is H2S is less than H2O due to:

Correct answer: D. All of the above

  • A. Small size of oxygen atom
  • B. Greater electronegativity of oxygen atom
  • C. Oxygen contains 2 lone pair of electrons
  • D. All of the above

Explanation

The bond angle in H2S is less than in H2O due to the smaller size of oxygen and the presence of two lone pairs of electrons on the oxygen atom. The smaller size of oxygen allows for closer electron-electron repulsion, resulting in a larger bond angle in H2O. Additionally, the presence of two lone pairs of electrons on the oxygen atom in H2O further increases the electron-electron repulsion, pushing the hydrogen atoms closer together and resulting in a smaller bond angle in H2S.

This question appeared on the KMU Centralized Admission Test 2021 paper, which you can sit online with every answer explained.

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About VSEPR Theory

Valence shell electron pair repulsion theory predicts molecular shape by arranging bonding pairs and lone pairs around a central atom to minimize repulsion. Questions cover linear, trigonal planar, tetrahedral, trigonal bipyramidal and octahedral electron geometries, bond angles and distortions caused by lone pairs. Electron geometry is not always the same as molecular shape.

Practise Chemical Bonding

964 free Chemical Bonding MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More VSEPR Theory questions