The beat frequency of two waves produced by two different tuning forks 505 Hz and 512 Hz will be
Correct answer: A. 7 Hz
- A. 7 Hz
- B. 6 Hz.
- C. 4 Hz.
- D. 0 Hz.
Explanation
The beat frequency of two waves is the absolute difference between their individual frequencies.Given: * Frequency of the first tuning fork (f1) = 505 Hz * Frequency of the second tuning fork (f2) = 512 HzThe formula for beat frequency (f_beat) is:f_beat = |f2 - f1|Calculation:f_beat = |512 Hz - 505 Hz|f_beat = 7 HzTherefore, the beat frequency is 7 Hz.Answer:The correct option is A) 7 Hz
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About Superposition and Interference
Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.
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