The average force necessary to stop a hammer with 25N·s momentum in 0.05 s expressed in 'N' is:
Correct answer: A. 500
- A. 500
- B. 125
- C. 50
- D. 25
Explanation
Average force = change in momentum / time = 25 N·s ÷ 0.05 s = 500 N. This is directly the impulse relation Favg Δt = Δp.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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