The atomic radius of transition elements in the periodic table _ along a period.
Correct answer: D. Decreases and then increases
- A. Increases
- B. Increases and then decreases
- C. Rapidly decreases and then becomes constant
- D. Decreases and then increases
Explanation
Over all trend can be explained based two factors that are working there, nuclear attractions and inter electronic repulsions, where one supports decrease in atomic radii and the other increase in atomic radii, respectively. As we are moving from Sc to Zn , initially one factor nuclear charge increases as the new electrons coming and entering into same orbital that to inner one, as the number of electrons are low in the inner shell and the shielding power of d orbial is low, inter electronic repulsions will be operating less than nuclear charge, which results in decrease in atomic radii. In the middle these two factors mostly operating equal, which results in consistency in size. In the end, as the number of electrons in the inner orbital increases the outer electrons feel better repulsions and slightly pushed away. Though d orbital has less shielding power, the number of electrons are too high to make the electronic repulsion as more dominant factor at the end, which results in increase in the atomic radii.
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About Transition Elements
Transition elements are identified by their partially filled d subshells in atoms or common ions. The topic covers the electronic structure of d-block elements, including the filling order of 4s and 3d orbitals, variable oxidation states and the distinction between transition elements and elements with completely filled d subshells.
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