The arrangement of sodium, oxygen, fluorine and strontium on the basis of increasing first ionization energy is
Correct answer: B. Sr < Na < O < F
- A. Na < Sr < O < F
- B. Sr < Na < O < F
- C. Sr < Na < F < O
- D. Na < Sr < F < O
Explanation
The correct arrangement of sodium (Na), oxygen (O), fluorine (F), and strontium (Sr) on the basis of increasing first ionization energy is:b. Sr < Na < O < FIonization energy is the energy required to remove an electron from an atom. Generally, ionization energy increases across a period (from left to right) and decreases down a group (from top to bottom) in the periodic table.In this case, Sr is a Group 2 (alkaline earth metal) element, Na is a Group 1 (alkali metal) element, and O and F are nonmetals.Among these elements, Sr will have the lowest first ionization energy, as it is in Group 2 and its outermost electrons are farther from the nucleus compared to Na in Group 1.Following the trend, Na < Sr < O < F is the correct order of increasing first ionization energy. Therefore, option b is the correct answer.
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