The apparent power drawn by an A.C. circuit is 10 kVA and active power is 8 kW. The reactive power in the circuit is_________?
Correct answer: B. 6 kVAR
- A. 4 kVAR
- B. 6 kVAR
- C. 8 kVAR
- D. 16 kVAR
Explanation
Using the power triangle, reactive power is Q = √(S² − P²) = √(10² − 8²) = 6 kVAR. The reactive component is therefore the remaining side of the apparent-power triangle.
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