The angular width of a central max. is 30o when the slit is illuminated by light of wavelength 6000 Å. Then the width of the slit will be approx.
Correct answer: B. 12 x 10^-7 m
- A. 12 x 10^-6 m
- B. 12 x 10^-7 m
- C. 12 x 10^-8 m
- D. 12 x 10^-9 m
Explanation
To find the width of the slit, we use the formula a = λ/sinθ. Given that the angular width θ = 30° and the wavelength λ = 6000 Å, we can calculate:a = 6000 Å / sin(30°) = 12000 × 10-10 m = 12 × 10-7 m.Therefore, the correct width of the slit is 12 × 10-7 m. Option B is the correct answer.Option A, C, and D are incorrect as they do not correctly apply the formula or calculate the width of the slit accurately.
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Light is studied through reflection, refraction, dispersion, interference, diffraction and polarization, linking ray behavior with its wave nature. Questions may involve mirrors, lenses, optical instruments, refractive index and image formation, while geometrical optics deals with rays and wave optics explains effects such as interference and diffraction.
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