The amplification factor of a triode is 20 and trans-conductance is 3 milli mho load resistance 3 x 10^4 Ω , then the voltage gain is:
Correct answer: A. 16.36
- A. 16.36
- B. 28
- C. 78
- D. 108
Explanation
To find the voltage gain (AV) of a triode, use the formula: AV = μ * gm * RL, where μ is the amplification factor, gm is the trans-conductance, and RL is the load resistance. Given μ = 20, gm = 3 milli mho = 0.003 S, and RL = 3 × 104 Ω, the calculation is:AV = 20 * 0.003 * 3 × 104 = 16.36.Therefore, Option A is correct. Other options result from incorrect calculations, likely due to errors in formula application or unit conversions.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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