The amount of work done in joule in carrying a charge+q along the closed path PQRSP between the oppositely charged metal plates is (Where E is the electric field between the plates):
Correct answer: A. 0 Joules
- A. 0 Joules
- B. E*q
- C. -E*q
- D. q*V
Explanation
The correct answer is Option A: 0 Joules. In electrostatics, the electric field is conservative, meaning that the work done in moving a charge around a closed path is zero. This is because the electric potential energy at the start and end points of the path is the same, leading to no net work being done. Options B, C, and D suggest scenarios where work is done, which isn't applicable to a closed path. Specifically, Option B implies direct work in a linear path, Option C suggests work against the field, and Option D applies to potential difference work, none of which fit a closed loop scenario.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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